160q^2-90=0

Solution for 160q^2-90=0 equation:

160q^2-90=0

a = 160; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·160·(-90)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*160}=\frac{-240}{320}
=-3/4
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*160}=\frac{240}{320}
=3/4
$